信息学奥赛一本通-2058:【例3.10】简单计算器

2023-05-23 07:11:02来源:哔哩哔哩

#include<algorithm>

#include<cmath>

#include<cstdio>


(资料图片)

#include<iostream>

using namespace std;

int main(){

float a,b;

char optr;

cin>>a>>b>>optr;

switch(optr){

case '+':

cout<<a+b;

break;

case '-':

cout<<a-b;

break;

case '*':

cout<<a*b;

break;

case '/':

if(b==0){

cout<<"Divided by zero!";

}

else{

cout<<a/b;

}

break;

default:

cout<<"Invalid operator!";

break;

}

return 0;

}

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